I may be wrong but no matter how many times i reanalyse these i get the same results (i reanalyse because people keep telling me i'm wrong)

Provided these two conditions:

- **Vesper Breastplate +0** is relatively easy to buy (there are many sell offers) and it's price is a stable 250kk adena

- EAS is represented by 10kk price and it's availability is unlimited

**Vesper Breastplate +4** will be worth __ exactly__ 435kk adena

**Vesper Breastplate +5**will be worth

**667,5kk adena**

__exactly__You might be thinking: Bullshiz you can't give a price to over-enchanted items because its all probability you can get lucky or unlucky it just doesn't make sense no matter how long you try the enchanted item cannot have a stable value blablablablablablablabla

Would you pay 2kkkk for **Vesper Breastplate +4**?

Would you pay 50kk for **Vesper Breastplate +4**? Gladly?

Would you pay 265kk for **Vesper Breastplate +4**? Why? Why not?

Imagine gamble like this: You pay 1$ and roll the dice. If you roll 6 you get 6$. Would you play it? Why is it a "fair" gamble? You can be lucky or unlucky if i roll two times and get 6 both times i get 10$ for free and if i roll ten times for nothing i lost 10$ its unfair!

The chance of success of over-enchanting any item piece by 1 is 2/3 (66,7%). That doesn't mean that from 3 tries you will get 2 successes - it's up to luck. But does indeed mean that __if you get 2 successes from 3 tries you're neither lucky nor unlucky.__ Also it means that probability_of_getting_3_successes*3xprice_of_succesfully_enchanted_breastplates ============= probability_of_loss*money_lost.

^ignore that line xD

If you get 2 successes from 3 tries you're neither lucky nor unlucky... That means that 2 new items should be worth the same as 3 old items plus price of all wasted EAS

x- price of new item (vesper breastplate +4, for example)

y- price of old item (vesper breastplate +3 in this example)

z- price of EAS

2x = 3y + 3z

x = 1,5y + 1,5z

This equation is easy enough to calculate without writing anything down (at least for me) but we can skip EAS (z) if you want:

x = 1,5y

That means that **Vesper Breastplate +4** should cost 50% more than **Vesper Breastplate +3. **Now scroll up to what i wrote about prices:

+0 - 250kk implies +3 280kk

+4 - 435kk = 280kk*1,5 + 10kk*1,5 (the equation)

+4 = 435kk

+5 = (435+10)*1,5 = 667,5kk

+6 = (667,5+10)*1,5 = 1kkk

From what i see many people say it's too high, but it's the only logical price. It doesn't come from the air, you know. If you sell it any lower you sell it underpriced, higher is overpriced, 1kkk is priced just right, period.

Dare to prove me wrong :P

After we should talk about roulette and how casinos are morons and giving money away for free.

Another thing about prices. Let's take the example of Skull Edge. Conditions:

- all these items have unlimited availability under their representing prices:

- 1kkk is a price that fully represents **Skull Edge +0**

- 70kk is a price that fully represents **EWS**

- 1kkk is a price that fully represents **SA**

- 500kk is a price that fully represents **150 element**

Remember how i said that thinking "you can't apply an even price to an over-enchanted item"? This doesn't apply here.**Skull Edge +0 through +14** **+SA/element** actually does NOT have once price.**Skull Edge +0 **+SA is NOT worth 2kkk. For that price you can get Skull Edge +0 AND items for SA separately - they're worth MORE when separate than when bound together. It's because of options: you have less possibilities with Skull Edge +0 +SA than with those items when they're separate. Maybe your buyer wants to enchant the weapon before putting SA?